Chemistry, asked by vansitav, 9 months ago

alpha-(D) glucose Bita(D) glucose, equilibrium
constant for this is 1.8. The percentage of alpha-(D)
glucose at equilibrium is
(1) 35.7
(2) 55.6
(3) 44.4
(4) 64.3​

Answers

Answered by Nazeeha06
1

Answer:

35.7 percent

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Answered by Aravindan123blast
3

Answer:

35.7

Explanation:

α(D)glucose⇌β−(D)−glucose

 

1−xx

x1−x=1.8

x=1.8−1.8x

2.8x=1.8

x=1.82.8=0.642

α−(D)glucose=(1−x)=1−0.642

x=0.358

Percentage of α−(D)glucose=0.358×100=35.8

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