Question

alpha, gama, betta are zeroes of the polynomial x^3-5x^2+7 then find the value of 1/ alpha+1/ gamma+ 1/ betta =

Answer 1

There is an error in the values I think

Answer 2

Answer:  comparing with a$x^{2}$+bx+c=0

a=6

b=3

c=-5

d=1

$\alpha \beta +\beta \gamma+\gamma\alpha$=c/a=-5/6

$\alpha \beta \gamma$=-d/a=1/6

$1/\alpha +1/\beta +1/\gamma$=$\beta \gamma+\alpha \gamma+\alpha \beta /\alpha \beta \gamma$

=-5/6*6/1

=5

This may help you