Question

Also answer Q25(b) .

Answer 1

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$25.(b) \\ we \: \: know \: \: that \: \: sum \: \: of \: \: all \\ angles \: \: of \: \: quadrilateral \: is \\ 360°.$

$x° + 2x °+ 13° + 3x° + 10° + x° - 6° = 360° \\ \\ = > 7x° + 17 °= 360° \\ \\ = > 7x °= 360 °- 17 °= 343° \\ \\ = > x° = \frac{343°}{7} \\ \\ = > x = 49°$

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