also explain how to do such questions
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this is question of balancing
here you should ensure that each number of atoms of particular element on both sides are equall
for ex in (1)
Al+HCL--------->AlCl3 +H2
here
left handside right handside
no. of atoms no. of atoms
AL =1 AL=1
CL =1 CL=3
H=1 H=2
here you can see Al is balanced already !
chlorine is not balanced
so , multiply 3 to HCL
you will see..
AL+3HCL ------> ALCL3 +H2
now CL and AL balanced only hydrogen is left
now multiply 3/2 to hydrogen
.
AL+3HCL ---->AlCl3 + 3/2H2
====> 2AL +6HCL ---->2AlCl3 + 3H2
now i hope you can do all by this method !
here you should ensure that each number of atoms of particular element on both sides are equall
for ex in (1)
Al+HCL--------->AlCl3 +H2
here
left handside right handside
no. of atoms no. of atoms
AL =1 AL=1
CL =1 CL=3
H=1 H=2
here you can see Al is balanced already !
chlorine is not balanced
so , multiply 3 to HCL
you will see..
AL+3HCL ------> ALCL3 +H2
now CL and AL balanced only hydrogen is left
now multiply 3/2 to hydrogen
.
AL+3HCL ---->AlCl3 + 3/2H2
====> 2AL +6HCL ---->2AlCl3 + 3H2
now i hope you can do all by this method !
zahraktab12:
yeah thanks it was helpful
why did you do
why did you multiply 3/2 to hydrogen
look it closely you will see that after balancing aluminium and chlorine , only hydrogen left on ons side hydrogen is 3 and on right side hydrogen was only 2 so i multiply 3/2 to right side of hydrogen so that it can become 3 as......(3/2×2)=3 therefore i made the right side hydrogen also 3....
and hence without affecting others i balanced
ok got it thanks
Answered by
0
I only know the answer of second and third
1.3Fe+4H2o=Fe3o4+4H2
Cl2+2kbr=2kcl+Br2
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