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Explanation:
excess charge on the oil drop will experience a electric field and a gravitational field in downward direction
the total numbers of oil drops =n
so the excess charge=neE
gravitational force =Mg= (ρ-ρ₀)4/3πr³g
they are equal
so neE = (ρ-ρ₀)4πr³g/3
n= (ρ-ρ₀)4πr³g/3eE excess eletrons
venky14800:
was it help full dear
magnitude is correct but there will be deficiency of electron
oh ok thank u very much for the correction
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