Math, asked by sangeetakushwaha2, 5 months ago

Also, it is given that the sum of the digits is 11.
x + y = 11
Solving (1) and (in), we get x = 8, y = 3. Hence the number is 308.
Exercise 5A
1. The sum of the digits of a 2-digit number is 9. The number is 6 times the units digit. Find the number.
2. The sum of the digits of a 2-digit number is 7. If the digits are reversed the new number increased by 3
less than 4 times the original number. Find the original number.
3. The sum of a number of 2 digits and of the number formed by reversing the digits is 110, and the difference
of the digits is 6. Find the number.
4. A certain number between 10 and 100 is 8 times the sum of its digits, and if 45 be subtracted from it the
digits will be reversed. Find the number.
5. A number consists of three digits, the right-hand digit being zero. If the left hand and the middle digits
be interchanged the number is diminished by 180. If the left-hand digit be halved and the middle and
right-hand digits be interchanged the number is diminished by 454. Find the number.
Hint. Let the original number be 100a+10b+0. i.e., 100a+10b, then, by the first condition
(100a+10b)-(100b + 10a) = 180 = a - b = 2
By the second condition, new number = 100 =+0+ b = 50a + b
and so (100a+10b) - (50a + b) = 454 50a + 9b = 454].
a
Deducing the Divisibility Test Rules of 2, 3, 5, 9, 10 for a 2- or 3-Digit​

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Answered by shyma00
1

Answer:

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Answered by userasheeralikhan42
0

Answer:

hi

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