Question

also please tell me the question number 23,24,28

Answer 1

what is the answer of 28?

Answer 2

24 )

Let the larger number be x
and smaller number be y

15 times of larger number :- 15x

5 times of smaller number :- 5y

When added gives 50

15x + 5y = 60

( dividing both side by 5 )

3x + y = 12

Our required linear equation is
3x + y = 12

y = 12 - 3x ..... ( i )

Put the value of x and get the value of y

If x = 2

y = 12 - 3x

y = 12 - 6

y = 6

( x , y ) :- ( 2 , 6 ) .... ( ii )


If x = 3

y = 12 - 9

y = 3

( 3 , 3 ) ..... ( iii )

If x = 4

y = 12 - 12

y = 0

( 4 , 0 ). .... ( iv )

Plot ( ii ) , ( iii ) and ( iv ) on graph .


28 )

$p = \frac{ \sqrt{5} - \sqrt{3} }{ \sqrt{5} + \sqrt{3} }$

$p = \frac{ \sqrt{5} - \sqrt{3} }{ \sqrt{5} + \sqrt{3} } \times \frac{ \sqrt{5} - \sqrt{3} }{ \sqrt{5} - \sqrt{3} }$
$p = \frac{ {( \sqrt{5} - \sqrt{3}) }^{2} }{5 - 3}$

$p = \frac{5 + 3 - 2 \sqrt{15} }{2}$

$p = \frac{8 - 2 \sqrt{15} }{2}$


$p = \frac{2(4 - \sqrt{15}) }{2}$
p = 4 - √15

$q = \frac{ \sqrt{5} + \sqrt{3} }{ \sqrt{5} - \sqrt{3} }$

$q = \frac{ \sqrt{5} + \sqrt{3} }{ \sqrt{5} - \sqrt{3} } \times \frac{ \sqrt{5} + \sqrt{3} }{ \sqrt{5} + \sqrt{3} }$

$q = \frac{ {( \sqrt{5} + \sqrt{3} )}^{2} }{5 - 3}$

$q = \frac{5 + 3 + 2 \sqrt{15} }{2}$

$q = \frac{8 + 2 \sqrt{15} }{2}$

$q = \frac{2(4 + \sqrt{15} )}{2}$
q = 4 + √15

To find :-

p²+ q²


( 4 - √15 )² + ( 4 + √15 )²

16 + 15 - 8√5 + 16 + 15 + 8√15

32 + 30

= 62