Question

also solve the q plz​

Answer 1

Answer:

$\boxed{\mathfrak{(a) \ 100 \ m}}$

Given:

Initial velocity (u) = 10 m/s

Final velocity (v) = 0 m/s

Acceleration (a) = -0.5 m/s²

To Find:

Distance covered (s) by scooter before it stops

Explanation:

$\sf From \ 3^{rd} \ equation \ of \ motion: \\ \boxed{ \bold{ {v}^{2} = {u}^{2} + 2as}}$

Substituting value of v, u & a in the equation:

$\sf \implies {(0)}^{2} = {(10)}^{2} + 2( - 0.5)s \\ \\ \sf \implies 0 = 100 + ( - 1)s \\ \\ \sf \implies 0 = 100 - s \\ \\ \sf \implies s = 100 \: m$

$\therefore$

Distance covered (s) by scooter before it stops = 100 m

Answer 2

☃ Given:-

• Initial Velocity = 10m/s.

• Final Velocity = 0m/s.

• Acceleration = -0.5m/s²

☃ To Find:-

• Distance Covered By Car.

☃ Solution :-

We can use the 3rd Equation Of Motion,

v² = u² + 2as.

Here,

v = Final Velocity,

u = Initial Velocity,

a = Acceleration,

s = Distance$.$

➮0² = 10² + 2 × 0.5 × s.

➮0 = 100 + s.

➮s = 100m.

Hence, Distance = 100m.