Question

alternating current in circuit is given as i=i1+i2cos wt the mean value of this current

Answer 1

Answer:

The RMS value of the current can be given by Irms  = √[(I₁² + I₂²)/2] Explanation :

Given,

I = I₁coswt + I₂sinwt

we know that sin of a function can be written in terms of cos

hence,

I = I₁coswt + I₂cos(wt - 90)

here the component I₂cos(wt - 90) is lagging the component I₁coswt by 90 degree,

So there vector sum can be written as,

I = √(I₁² + I₂² + 2I₁I₂cos90)

=> I = √(I₁² + I₂²)

=> Irms  = √[(I₁² + I₂²)/2]

Hence the RMS value of the current can be given by Irms = √[(I₁² + I₂²)/2]

Explanation:

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