Alternating voltage is given across P and Q and output is taken across S and T choose the correct for output voltage
Answers
Explanation:
Let's say we put a very little positive energy, like +0.2+0.2plus, 0, point, 2 volts, over a silicon diode. This sets us on the right-hand side of the iii-vvv curve. By this little positive voltage, virtually no forward contemporary flows. If the voltage rises to about 0.6\,\text V0.6V0, point, 6, incite text, V, end text measured current commence to flow into the diode progressively. As the energy goes a little high 0.6\,\text V0.6V0, period, 6, start a text, V, end text, the current over the diode increases fast. The iii-vvv curve is nearly vertical at this point.
With a positive charge on its ends, we assume the diode is forward biased. A diode is forward biased when its charge is everywhere on the ++plusvoltage top of the rise. In whole process, the charge over a forward-biased silicon diode is around within 0.60 -0.75\,\text V0.60−0.75V0, point, 60, minus, 0, point, 75, start a text, V, end text. If you externally apply the energy essential than 0.750.750, point, 75 volts, the diode flow gets very high and it may heat.
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