alternative :
53. If P(x) = (x - 1) (x + 2) (x - 3) then P(0) = ?
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If P(x) = (x - 1) (x + 2) (x - 3) then
P(0) = (0-1)(0+2)(0-3)
= -1 + 2 -3
= -2
is the answer buddy
Answered by
2
Given that :
P(x) = (x - 1)(x + 2)(x - 3)
On putting x = 0 :
P(0) = (0 - 1)(0 + 2)(0 - 3)
=> P(0) = -1 × 2 × (-3)
=> P(0) = 6
@ItsChampion ✌️
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