Question

Altitude and base of a triangle are 56 cm and 42 cm respectively. Area of the triangle is -----------​

Answer 1

Answer:

area= base × hight × 1/2

therefore

area = 56×42×1/2

=1176 (ANSWER )

Answer 2

Answer:

Hence the area of the triangle is $1176\;cm^{2}$

Step-by-step explanation:

As per the data provided in the given question.

The given data is as follows,

Altitude of triangle is 56 cm and base of triangle(b) is 42 cm

We have to the value of area of triangle (A).

Altitude represent the height of triangle i.e. (h).

Here we will be using the formula of area of triangle.

$A=\frac{1}{2}\times b\times h$

Now we will substitute the value of base and height in above formula.

$A=\frac{1}{2}\times42\times56$

Now we will divide 56 by 2  

$A=1\times42\times28\\A=42\times28$

Now we will multiply 42 into 28

Further, we get

$A=1176\;cm^{2}$

Hence the area of the triangle is $1176\;cm^{2}$