Question

Altitude of a right prism is 10 centimetre and its base is an equilateral triangle of side 12 cm then its total surface area is

Answer 1

Step-by-step explanation:

total surface area of prism = ph + 2b

p is perimeter of base

h is height of prism

b is area of base

perimeter of base = 12 + 12 + 12 = 36

height of prism = 10

area of base = √3/4 a^2

$= \frac{ \sqrt{3} }{4} \times {12}^{2} \\ = \frac{ \sqrt{3} }{4} + 144 \\ = \sqrt{3} \times 36 \\ = 1.732 \times 36 \\ = 62.352$

tsa of prism = pH + 2b

$= (36 \times 10) + 2(62.352) \\ = 360 + 124.704 \\ = 484.704$

hope you get your answer