Question

Altitude of parallelogram of area 4.68m2and base 36dm

Answer 1

$\huge\mathbb{SOLUTION:-}$

$\bold{Given}\begin{cases}\sf{A\: parallelogram}\\ \sf{Base=36dm\: or\: 3.6m}\\ \sf{Area=4.68m{}^{2}}\end{cases}$

$\huge\sf{To\:Find:-}$

The altitude of parallelogram

$\boxed{\sf{Area\:of\: parallelogram=Base\:times height}}$

$\bf\underline{\red{According\:to\: Question:-}}$

$\sf\implies Area=base\times altitude\\ \\ \sf\implies 4.68=3.6\times altitude\\ \\ \sf\implies \frac{4.68}{3.6}=altitude\\ \\ \sf\sf\implies \cancel{\frac{4.68}{3.6}}=altitude\\ \\ \sf\implies altitude=0.13m$

$\boxed{\sf{\purple{Altitude\:of\: parallelogram=0.13m}}}$

• Now let's verify our answer is correct or not

$\large\boxed{\sf{\red{VERIFICATION:-}}}$

$\sf\implies Area=base\times height\\ \\ \sf\implies 6.48m{}^{2}=3.6m\times 0.13m\\ \\ \sf\implies 4.68m{}^{2}=4.68m{}^{2}$

$\sf L.H.S=R.H.S\:\:\:\mathfrak{\underline{hence\: verified!!}}$

• altitude=0.13m or
• 0.13×10=1.3dm

$\boxed{\sf{\red{Altitude=1.3dm}}}$

#BAL

#answerwithquality

Answer 2

Answer:

13 dm

Step-by-step explanation:

Answer in the attachment!!