Altitudes MN and MO of parallelogram MGHK are 8 cm and 4 cm long respectively. One
side GH is 6 cm long. Find the perimeter of MGHK.
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Given : Altitudes MN and MO of parallelogram MGHK are 8 cm and 4 cm long respectively.
One side GH is 6 cm long,
To Find : the perimeter of MGHK
Solution:
Altitude MN = 8 cm on GH = 6 cm
Then Area = (1/2) MN * GH
8 * 6 = 48 cm²
Also Area = MO * HK
=4 * HK
= 4HK
4HK = 48
=> HK = 12
Perimeter = 2 ( GH + HK)
= 2( 6 + 12)
= 36 cm
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