Math, asked by Anonymous, 1 year ago

aluate :x square tan inverse 1 by x square x square into tan inverse X upon 1 + x square ka integration

Answers

Answered by sanjaykumargupta568

0

Answer:

(i) ∫1·e^x (tan^(−1)⁡x+ 1/(1 + x^2 )) dx ∫1 ·〖e^x [tan^(−1)⁡〖x+1/(1+x^2 ) ...

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