Question

Aluminium crystallises in a ccp structure. Its metallic radius is 125 pm. Calculate the edge length of the cell.

Answer 1

Answer:354 pm (approximately)

Explanation:

For the cubic close–packed structure

Let a is the edge of the cube and r is the radius of atom

Given that r = 125 pm

a = 2√2 r

plug the value of r we get

= 2 x 1.414 x125 pm

= 354 pm (approximately)

Answer 2

Aluminium crystallises in a ccp structure. Its metallic radius is 125 pm. The edge length of this cell is 354 pm.

Explanation:

It is known that for cubic close packed structure (ccp) we assume that edge length is represented by "a" and radius of the atom is represented by "r".

It is given that radius (r) = 125 pm

For a ccp lattice, the relation between radius and edge length is as follows.

                  a = $2 \sqrt{2}r$

Hence, putting the given values into the above formula as follows.

               a = $2 \sqrt{2}r$

                 = [tex]2 \times 1.414 \times 125 pm [/tex]

                 = 354 pm (approximately)

Learn more about ccp structure:

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Learn more about edge length:

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