Question

aluminium hydroxide reacts with sulphuric acid to form aluminum sulphate and water.write a balanced equation for this reaction

Answer 1

The reaction is: 
2Al(OH)3 + 3H2SO4 →Al2(SO4)3 + 6H2O

Answer 2

Aluminum hydroxide is a base as it is hydroxide of metal which are basic in nature whereas sulphuric acid is an acid therefore reaction of acid and base will form salt and water $\left(\mathrm{H}_{2} \mathrm{O}\right)$. The reaction is called as neutralization reaction. Here sulphate salt of aluminum is formed with water.  

The balance equation for this reaction can be written as:

$2 \mathrm{Al}(\mathrm{OH})_{3}+3 \mathrm{H}_{2} \mathrm{SO}_{4} \rightarrow \mathrm{Al}_{2}\left(\mathrm{SO}_{4}\right)_{3}+6 \mathrm{H}_{2} \mathrm{O}$

$\begin{array}{l}{\text { Aluminum hydroxide + Sulphuric acid } \rightarrow \text { Aluminum }} \\ {\text { sulphate + Water }}\end{array}$