Question

aluminium reacts with oxygen to form Aluminium oxide and weight of al is 34 and cl is 39 find limiting reagent and weight of product​

Answer 1

Answer:

The chemical equation for combustion of Al in oxygen

4Al + 3O2 = 2Al2O3

Molar mass of Al = 27 g

Molar mass of Oxygen molecule = 32 g

Hence the Al and oxygen reacted in 1:1 molar ratio

Al is the limiting reactant as there is not sufficient of it to react with excess oxygen, as from the equation 1 mole of Al forms half mole of aluminium oxide, the molar mass of aluminium oxide is 27*2 + 16*3 = 102

Hence mass of Aluminium oxide formed = 102/2=51 g

Explanation: