aluminium sulphate reacts with sodium hydroxide to give white precipitate of aluminium hydroxide and sodium sulphate
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With dilute NaOH(sufficient), Al2(SO4)3 + 6NaOH → 2Al(OH)3 + 3Na2SO4.
With concentrated NaOH(excess), Al2(SO4)3 + 8NaOH → 2Na[Al(OH)4] +3Na2SO4.
At higher temperature, Al2(SO4)3 + 8NaOH → 2NaAlO2 + 3Na2SO4 + 4H2O.
Note: Na[Al(OH)4] is the hydrated form of NaAlO2 and at higher temperature, water is released.
With dilute NaOH(sufficient), Al2(SO4)3 + 6NaOH → 2Al(OH)3 + 3Na2SO4.
With concentrated NaOH(excess), Al2(SO4)3 + 8NaOH → 2Na[Al(OH)4] +3Na2SO4.
At higher temperature, Al2(SO4)3 + 8NaOH → 2NaAlO2 + 3Na2SO4 + 4H2O.
Note: Na[Al(OH)4] is the hydrated form of NaAlO2 and at higher temperature, water is released.
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Answer:
Explanation:
Al2(SO4)3 + 6NaOH GIVES 2Al(OH)3 + 3Na2So4
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