Question

aluminium wire of cross-section 3 x 10-4 m2 has a length of 51 m. If the resistivity of
aluminium is 2.6 x 10-8

ohm.m, what would be the resistance of the wire?

Answer 1

Explanation:

R=(rho)l/A

R=2.6*10^-8(51)/3*10^-4

R=0.000000026(51)/0.00003

R=0.0442 ohm

Answer 2

CORRECT QUESTIONS:

Aluminum wire of cross section 3 × 10-⁸ m² has a length 51m . If the resistivity of aluminium is 2.6 × 10-⁸Ω . What would be the resistance of wire

ANSWER:

We know that

R = ρ( I )/A

Where

• R = ?
• ρ = 2.6 × 10-⁸
• I = 51
• A = 3 × 10-⁴

Substituting the values we have

→ R = 2.6×10-⁸( 51 )/3×10-⁴

→ R = 2.6 × 10-⁴(51)/3

→ R = 0.00026(51)/3

→ R = 0.01326/3

→ R = 0.00442 Ω

Hence, resistance of wire = 0.00442Ω