Aluminium wire of resistance R is pulled so that its length become 4 times its original length. Find the new resistance of the wire in terms of its original length.
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Given that ,
Resistance of wire = R ohm
let the length of wire be l
We know that,
R is directly proportional to the length of conductor.
Therefore,
The resistance also becomes 4 times its original resistance and its area becomes 1/4 of its original cross sectional area.
Hence, Resistance of wire is 4l/1×A/4=16l/A
Resistance of wire = R ohm
let the length of wire be l
We know that,
R is directly proportional to the length of conductor.
Therefore,
The resistance also becomes 4 times its original resistance and its area becomes 1/4 of its original cross sectional area.
Hence, Resistance of wire is 4l/1×A/4=16l/A
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