Chemistry, asked by sanjaykadu325, 10 months ago

Aluminum crystallize in cubic close packed structure with unit cell edge length of 353.6 pm.what is the radius of Al atom? How many unit cell are there is n 1.00 cm^3 of Al ?

Answers

Answered by Jasleen0599
24

Given:

Aluminium crystallize in cubic close packed structure.

a = 353.6 pm = 353.6 × 10⁻¹⁰ cm

Volume of Al = 1 cm³

To Find:

The radius of Al atom and the no of unit cells in the given volume of Al.

Calculation:

- For ccp structure, we know that:

r = a / (2√2)

⇒ r = 353.6 / (2√2)

r = 125.035 pm

- Volume of 1 unit cell of Al = a³

⇒ V = (353.6 × 10⁻¹⁰)³

⇒ V = 44.212 × 10⁻²⁴ cm³

- No of unit cells = Volume of Al/Volume of 1 unit cell

⇒ N = 1/44.212 × 10⁻²⁴

N = 2.262 × 10²²

- So, the radius of Al atom is 125.035 pm and the no of unit cells in 1 cm³ of  Al is 2.262 × 10²².

Answered by DurgaHarad
2

I hope this is helpful....

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