Question

Aluminum reacts with chlorine to form aluminum chloride. The equation for this
reaction is 2 Al(s) + 3 Cl2(g) 2 AlCl3(s). What is the percentage yield for a reaction in which 33.5 g of aluminum is reacted with excess chlorine to produce 164.5 g of aluminum chloride?

Answer 1

Explanation:

· reaction is 2 Al(s) + 3 Cl2(g) 2 AlCl3(s). What is the percentage yield for a reaction in which 33.5 g of aluminum is reacted with exce

Answer 2

Given:

Mass of Aluminium = 33.5 gm

Mass of Aluminium Chloride = 164.5 gm

To Find:

Percentage yield of the reaction.

Calculation:

- According to the given reaction:

2 Al (s) + 3 Cl₂ (g) → 2 AlCl₃ (s)

54 gm of Al reacts forms AlCl3 = 267 gm

⇒ 33.5 gm of Al will produce AlCl3 = (267/54) × 33.5 = 165.64 gm

- Percentage yield = (Actual yield / theoretical yield) × 100

⇒ % yield = (164.5/165.64) × 100

⇒ % yield = 99.31 %

- So the percentage yield for the given reaction is 99.31 %.