Aluminum wire has radius 0.25mm and length 15m .If resistance of wire is 10ohm ,find the resistivity of the wire
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Answer:
1.306 × 10⁻⁷ Ω m
Explanation:
Given :
Radius r = 0.25 mm = 0.25 × 10⁻³ m
= > Area of cross section = 0.25² × 10⁻⁶ π m²
Length L = 15 m
Resistance R = 10 Ω
We are asked to find resistivity ρ :
We know :
R = ρ L / A
= > ρ = R A / L
= > ρ = ( 10 × 0.25² × 10⁻⁶ π ) / 15 Ω m
= > ρ = ( 10 × 0.0625 × 10⁻⁶ π ) / 15 Ω m
= > ρ = ( 0.625 × 10⁻⁶ π ) / 15 Ω m
= > ρ = ( 0.0416 × 10⁻⁶ π ) Ω m
= > ρ = 0.1306 × 10⁻⁶ Ω m
= > ρ = 1.306 × 10⁻⁷ Ω m
Therefore , the resistivity of the wire is 1.306 × 10⁻⁷ Ω m.
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