Question

alzebric expression factorise​

Answer 1

4(p+q)(3a-b)+6(p+q)(2b-3a) = 2(p+q)[2(3a-b) + 3(2b-3a)] = 2(p+q)[6a - 2b + 6b - 9a] = 2(p+q)[4b - 3a]