Question

AM (arithmetic mean) of 2^10,4^8,16^9 and 64^5 is​

Answer 1

Given the numbers are 2,4,6,8,10,12,14, and 16

The mean of a set of numbers is the sum divided by the number of terms.

Then, mean =

8

2+4+6+8+10+12+14+16

=

8

72

=9