Math, asked by blink24092009, 3 days ago

AM=BM=CM
Angle ACB=?​

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Answered by amannscharlie
1
  • According to given things on your book

  • m is the midpoint so MB = AM = CM and is equal to height.

  • if we see then there two isosceles triangle in one triangle.

  • angle CM is 90° because height is perpendicular.

  • then two remaining sides will be 45 ° ..as 180 - 90 = 90° half of 90° is 45°

  • so angle ACB = 45° + 45° = 90°

  • refer attachment if you don't understand ✅

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