AM=BM=CM
Angle ACB=?
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- According to given things on your book
- m is the midpoint so MB = AM = CM and is equal to height.
- if we see then there two isosceles triangle in one triangle.
- angle CM is 90° because height is perpendicular.
- then two remaining sides will be 45 ° ..as 180 - 90 = 90° half of 90° is 45°
- so angle ACB = 45° + 45° = 90°
- refer attachment if you don't understand ✅
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