Question

am equivalent to 5/6. the sum of my numerator and my denominator is44. the sum of the digits in my denominator is 6​

Answer 1

$\huge{ \bf{ \pink{ \mid{ \underline{ \overline{ \green{work \: out...}}}}}}}$

$\large{ \huge{ \red{{question...}}}}$

• Find an equivalent to 5/6. the sum of my numerator and my denominator is44. the sum of the digits in my denominator is 6...?

$\huge{ \red{ to \: find... }}$

$\large{ \sf{ \ \frac{a}{b} such \: that \: \frac{a}{b} = \frac{5}{6} and \: a + b = 44}}$

$\huge{ \red{solution..}}$

$\large{ = > \frac{a}{b} = \frac{5}{6}(given) } \\ = > \large{ 6a = 5b} \\ = > \large{a = \frac{5b}{6} }$

$\large{we \: know..a + b = 44 }\\ { \large{ = > \frac{5b}{6} + b = 44}} \\ \large{ = > \frac{5b + 6b}{6} = 44} \\ \large{ = > \frac{11b}{6} = 44} \\ \large{ = > b = \frac{44 \times 6}{11} } \\ \large{ = > b = 24}$

$\large{then \: a = \frac{5 \times 24}{6} } \\ = > \large{a = 5 \times 4} \\ = > \large{a = 20}$

$\large{also \: b = 24 }\\ \large{ and \: sum \: of \: digits = 2 + 4 = 6}$

$\large{ \green{final \: answer = > \frac{a}{b} = \frac{20}{24} }} \\ (\blue{ \bold{answer}})$

$\large{ \bold{ \red{ running \: in \: an \: endless \: maze ..}}}$

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