AM is a median of a ΔABC
Is AB + BC + CA > 2AM ?
Please please please explain properly
Attachments:
Answers
Answered by
34
Heya Princess !
--------------------
Given that ,
---------------
◾AM is a Median Of ∆ABC ,
◾In ∆ABM ,
=> AB + BM > AM ......................(1)
[ As sum of two sides of a Triangle is greater than the third side ]
Again in ∆ACM ,
=> AC + CM > AM.....................(2)
◾Now, Adding Equation (1) and (2) ,
We get ,
=> AB + BM + AC + CM > AM + AM
=> Now, BM + CM = BC
◾Equation becomes ,
=> AB + BC + CA > 2AM.
✔Hence Proved !!
=========================================================
--------------------
Given that ,
---------------
◾AM is a Median Of ∆ABC ,
◾In ∆ABM ,
=> AB + BM > AM ......................(1)
[ As sum of two sides of a Triangle is greater than the third side ]
Again in ∆ACM ,
=> AC + CM > AM.....................(2)
◾Now, Adding Equation (1) and (2) ,
We get ,
=> AB + BM + AC + CM > AM + AM
=> Now, BM + CM = BC
◾Equation becomes ,
=> AB + BC + CA > 2AM.
✔Hence Proved !!
=========================================================
PrincessNumera:
Ohh
Now I understood
Tysm
Thank God xD
Tysm to Hume bolna chahiye
XD
Dhanyawaad Meli Princess :)
:)
Fabulous answer..... ^•^
Thanka❤
Answered by
7
Answer in attachment follow it Thanks
Attachments:
Tysm
Similar questions