AM is a median of a ∆ABC.Prove that AB+BC+CA>2AM.
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In triangle ABM
AB+ BM > AM…….(1)
In rriangle ACM
AC + CM > AM…….(2)
By adding the equation 1 & 2 we get
AB + AC +( BM+CM) > 2AM
where BM +CM = BC ( acc. to figure)
Hence …. AB + BC + CA > 2 AM
PROVED………..
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