Question

AM is a median of A ABC. Prove that (AB+BC+CA) > 2AM.


please answer now it's urgent​

Answer 1

Answer:

Using the inequality of the triangle that the sum of any two sides is always greater than or equal to the third side. Hence AB+BC+CA>2AM is proved to be true.

HOPE THIS HELPS YOU

PLS MARK ME AS THE BRIANLIEST

Answer 2

Step-by-step explanation:

that answer is the correct answer