Question

AM is a median of a angle ABC. prove that (AB+BC+CA)→2(AM)​

Answer 1

Step-by-step explanation:

(AB+BM)>AM (In ABM)

(AC+MC)>AM (In ACM)

Now , add the two inequalities .

Answer 2

Answer:

Using the inequality of the triangle that the sum of any two sides is always greater than or equal to the third side. Hence AB+BC+CA>2AM is proved to be true.