AM is a median of a triangle ABC. Is AB + BC+CA > 2 AM?
(Consider the sides of triangles ABM and AMC.)
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Step-by-step explanation:
Sum of 2 sides > third side
In the triangle ABM = 1st triangle
AB + BM > AM
In triangle AMC = 2nd triangle
CA + CM > AM
Now, According to the question:
Adding 1st and 2nd triangle
AB + BM + CA + CM = AM + AM
Hence,
AB + BC + CA = 2(AM)
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