AM is a median of a triangle ABC.
Is AB + BC + CA>2 AM?
(Consider the sides of triangles
AABM and AAMC.)
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Answer:
We know,
In a triangle sum of two sides is greater than the third side
Hence,In triangle ABM
AB + BM > AM .........1
Also in triangle ACM
AC + MC > AM ..........2
Adding equation 1 and 2 we get,
AB + BM + AC + MC > AM + AM
AB + AC + (BM + MC) > 2AM
AB + AC + BC > 2AM
Step-by-step explanation:
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