AM is a median of a triangle ABC
Is AB+BC+CA> 2 AM?
(Consider the sides of triangles ABM and AMC. )
Answers
Answered by
17
In ∆ ABM ,
AB + BM > AM [ Sum of two sides is greater than the third side ].................(1)
In ∆ ACM ,
AC + CM > AM [ Same Reason ]...........(2)
Adding (1) & (2) , we get
AB + AC + BM + CM > AM + AM
AB + BC + AC > 2AM .
Hence , Proved .
Answered by
1
Answer:
Refer to the attachment above. ⬆️
hope it helps!!
Attachments:
Similar questions