AM is a median of triangle ABC. Prove that(AB + BC + CA) >2AM
Answers
Answered by
1
Answer:
IN triangle ABM
AB+BM>AM EQ-1
ALSO IN TRIANGLE ACM
AC+MC>AM EQ-2
ADD EQ-1 AND EQ-2
AB+BM+AC+MC>AM+AM
AB+AC+(BM+MC)>2AM
HENCE PROVED
AB+AC+BC>2AM
Answered by
0
Answer:
In triangle ABMC we have,
AB+BM>AM....(i)
In triangle AMC we have,
AC+CM>AM....(ii)
Adding equation (i) and (ii) we get
AB+AC+BM+CM>AM
AB+AC+BC>2AM
AB+BC+CA>2AM
Hence proved
Similar questions