Question

AM is altitude in an equilateral triangle ABC with length of its side 12 cm what is length of AM in cm​

Answer 1

Answer:

AM=

$6 \sqrt{3}$

Step-by-step explanation:

in triangle ABC

AB=BC=AC=12cm

AM is a altitude on side BC

BM=MC=1/2 ×BC

BM=MC=6cm

in triangle AMB

M=90°____(AM is altitude)

by pythagoras theorem

AB²=AM²+MB²

(12)²=AM²+(6)²

144-36=AM²

AM²=108

AM=

$6 \sqrt{3}$