Question

AM is the median of Triangle ABC,Prove that ( AB +BC+CA ) > 2AM​

Answer 1

Answer:

We know,

In a triangle sum of two sides is greater than the third side

Hence,In triangle ABM

AB + BM > AM .........1

Also in triangle ACM

AC + MC > AM ..........2

Adding equation 1 and 2 we get,

AB + BM + AC + MC > AM + AM

AB + AC + (BM + MC) > 2AM

AB + AC + BC > 2AM

Step-by-step explanation:

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