AM is the medion of a ABC. pove that
AB+ BC + CA > AB
=
Answers
Answered by
0
Answer:
Using the inequality of the triangle that the sum of any two sides is always greater than or equal to the third side. Hence AB+BC+CA>2AM is proved to be true. Note: The proof is valid in general even if AM is not the median of the triangle.
Step-by-step explanation:
this is you answer this may help you a lot ♥️♥️
Similar questions