Question

Amal is twice as old as his sister. Six years ago, his age was 4 times sister's age. Find their present ages.​

Answer 1

Answer:

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Answer 2

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$\\ \\ \\ \\ \\ let \: \\ \\ age \: of \: { \red{Arjun}} \: be \: \: = x \\ \\ age \: of \: { \red{Shriya}} \: be \: \: = y \\ \\ \\ then \\ \\ \\ ATQ \\ \\ \\ x = 2y \: \: \: - - - (1) \\ \\ \\ and \: five \: years \: ago \\ \\ \\ x - 5 = 3(y - 5) \\ \\ \implies \: x - 5 = 3y - 15 \\ \\ \implies x - 3y + 10 = 0 \: \: \: - - - (2) \\ \\ \\ using \: (1) \\ \\ \\2y - 3y + 10 = 0 \\ \\ \implies y = 10 \\ \\ \implies x = 20 \\ \\ \\ \\ \\ { \pink{\fbox{age \: of \:Arjun = 20 \: \: yrs }}} \\ \\ \\ \\ { \pink{\fbox{age \: of \: Shriya = 10 \: \: yrs }}}$

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