Question

Amalu's father's age is 6 years more than 7 times Amalu's age. Find Amalu's age, if his father is 48 years old.


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Answer 1

Answer:

Let,

Amalu's age = x

Amalu's father's age = 7x + 6

Amalu's father is 48 years old.

* According to the Question :

→ 7x + 6 = 48

7x = 48-6

→ 7x = 42

⇒ x = 42/7

9= x=

Amalu's age = 6 years

• Amalu's father's age = 7x + 6

7 (6) + 6

⇒ 42 +6

→ 48

Amalu's father's age = 48 years (Given)

Therefore, Amalu's age = 6 years

It's No1.Kamina

Answer 2

To find :  Amalu's age  

Given : Amalu's father's age is $6$ years more than $7$ times Amalu's age.  

            His father's age is $48\ yrs$ .  

Solution :  

• Let , $x$ be the Amaul's age .
• As per the given data we know that Amalu's father's age is $6$ years more than $7$ times Amalu's age and his father's age is $48\ yrs$ .

• We represent given condition as ,

        $7x + 6 = 48$

              $7x = 42 \\x = 6$

Hence , Amaul's age is $6\ yrs$ .