Math, asked by milo21, 1 year ago

Aman age is 3 times his son's age 10 years ago he was five times his son's age find their present age​

Answers

Answered by chikki52
21

Answer:

A man's age is three times his son's age.Ten years ago he was five times his son's age.

By forming two equations and solving them simultaneously,find both of their ages.

:

Let m = man's present age

let s = son's present age

:

Write an equation for each statement:

:

"A man's age is three times his son's age"

m = 3s

m - 3s = 0

:

"Ten years ago he was five times his son's age."

m - 10 = 5(s-10)

m - 10 = 5s - 50

m - 5s = -50 + 10

 

m - 5s = -40

multiply by -1 to change the signs, add to the first equation

-m + 5s = 40

+m - 3s = 0

------------adding eliminates m, find s

2s = 40

s = 40/2

s = 20 yr is the son's age

then

m = 3(20)

m = 60 is the man's age

Answered by perpetuallyperplexed
16

Answer:

The son is 20 years old

Aman is 60 years old

Step-by-step explanation:

Let: -> Aman's age be A; -> His son's age be S.

A = 3S

A - 10 = (S-10) * 5 => A - 10 = 5S - 50 => A = 5S - 40

A = 3S = 5S - 40

=> 2S = 40

S = 20 years

A = 3S = 60 years

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