Math, asked by prettyqazws, 1 year ago

Aman age is three times his son age .Ten year ago he was 5 time his son age .find present ages.

Answers

Answered by IshitaXBisht
2
Let present age of Aman be x
present age of Aman's son be y
ATQ, x=3y
Ten years ago,
x-5=5(y-5)
x-5=5y-25
x-5y=-20
x-3y=0
x-5y=-20
- +     +
 2y=20
y=20
Present age of Aman = 60 years
Present age of Aman's son = 20 years
Answered by samiramishra
5

Solution-:

Solution: let present age of Aman son = x year

then,

present age of Aman= 3x year

10 year ago Aman son age x- 10 year

Aman age= 3x - 10

now according to questions-:

 \displaystyle \: 3x - 10 = 5(x - 10)

or

 \displaystyle3x - 10 = 5x - 50

or

 \displaystyle3x - 5x = 50 + 10

or

 \displaystyle - 2x =  - 40

or

 \displaystyle \: x=  \frac{ - 40}{ - 2} = 20

thus,, age of son is 20 year

and age of Aman= 3 × 20 =60

so present age of Aman is 60 year and present age of his son is 20 year Answer

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