Math, asked by prakash5720, 1 year ago

aman,baman and chaman can do a work in 15, 20 and 25 days. however, while working with someone efficiency of aman, baman and chaman reduces by 30%, 20% and 50%. none of them is allowed to work for 3 consecutive days. what is the maximum fraction of total work can be done in 4 days

Answers

Answered by sonabrainly
0

Let the job be of L.C.M.(15, 20, 25) = 300 units.

The number of units completed by Aman, Baman and Chaman in a day while working alone on the job are

20, 15 and 12 respectively.

The number of units completed by Aman, Baman and Chaman in a day while working on the job with

somebody else are 14, 12 and 6 respectively.

Aman, Baman and Chaman together complete 14 + 12 + 6 = 32 units of work in a day.

The number of units completed will be 32 + 20 + 18 + 32 = 102.

hence 102/300 = 17/50



prakash5720: here only have i to ask.. how in the last.. 32 for a, b and c.. 20 for a and c, 18 for b and c.,32 for a, b, c.. then c has work for conservative 4 days, surpassing the 3consecutive days.. .but its given in question none of them is allowed to work for 3 consecutive days.. then how its possible.. plz answer
Answered by NitinMohanty
0

Answer:

17/50

Step-by-step explanation:

Let the job be of L.C.M.(15, 20, 25) = 300 units.

The number of units completed by Aman, Baman and Chaman in a day while working alone on the job are

20, 15 and 12 respectively.

The number of units completed by Aman, Baman and Chaman in a day while working on the job with

somebody else are 14, 12 and 6 respectively.

Aman, Baman and Chaman together complete 14 + 12 + 6 = 32 units of work in a day.

The number of units completed will be :

A+B+C = 32

A+B = 26

C = 12 (working alone so efficiency = 12)

A+B+C = 32

Total Work = 102

hence 102/300 = 17/50

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