Question

Aman can throw a stone with velocity 20m/sec.Find the.maximum distance he can throw it on a horizontal plane at what height it will.rise?

Answer 1

Answer:

Explanation:

Let the speed by which the stone is thrown be  u making an angle θ with the horizontal.

∴ Horizontal range     R=gu2sin2θ​

For maximum horizontal range         θ=45o

⟹    Rmax​=gu2sin90o​=gu2​

80=10u2​             ⟹u2=800

Let maximum height it attains be  H

∴   H=2gu2sin2θ​                 where   θ=45o

H=2gu2sin245o​=2×10800×21​​=20 m