Math, asked by rsibashankar, 11 months ago

aman had three animals. and he also owns a pasture horse and cow can eat the contents of pasture in 40 days .cow+sheep =60 days and horse+sheep =90 days then cow+horse+sheep can eat the food??please explain ​

Answers

Answered by btslover222006
3

Answer:

here is the answer

Step-by-step explanation:

Since it takes horse the horse and the cow 40 days. In I day ¹⁄₄₀ of the pasture would be eaten, since it takes the horse and the sheep 60 days, in 1 day ¹⁄₆₀ would be grazed, since it takes the cow and the sheep 90 days, in 1 day ¹⁄₉₀ of the pasture would be devoured.

¹⁄₄₀ + ¹⁄₆₀ + ¹⁄₉₀ = ¹⁹⁄₃₆₀

¹⁹⁄₃₆₀ equals what 2 horses, 2 cows and 2 sheep eat in a day and

¹⁹⁄₃₆₀ ÷ 2 = ¹⁹⁄₇₂₀

¹⁹⁄₇₂₀ equals what 1 horse, 1 cow and 1 sheep eat in 1 day.

As it takes to eat ¹⁄₇₂₀ of the contents of the pasture ¹⁄₇₂₀ will require 19th part of 1 day or 720/ 720 or the whole of the contents of the pasture will require 720 times as many days.

Or 37 - ¹⁷⁄₁₉

19: 1: 720: 37 - ¹⁷⁄₁₉

at 21:59

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