Question

Aman obtained 410 marks out of 500 in CBSE XII examination while his brother
Anish gets 536 marks out of 600 in IX class examination.Find whose
performance is better by finding out the percentage.

Answer 1

Given :

• Aman got 410 marks out of 500 in CBSE XII examination
• Anish got 536 marks out of 600 in IX class examination

To find :

• Find percentage of both.
• Find whose performance is better.

Formula used :

Percentage = Marks obtained × 100/ Maximum marks

Solution :

First of all we need to find percentage of both, and therefore we will compare Percentage obtained by both ( the more is percentage better is performance )

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Percentage of Aman = (Marks obtained by Aman × 100) ÷ ( Maximum marks)

➝ Percentage of Aman = ( 410 × 100) ÷ ( 500)

➝ Percentage of Aman = 41000 ÷ 500

➝ Percentage of Aman = 82%

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Percentage of Anish = (Marks obtained by Anish × 100) ÷ ( Maximum marks)

➝ Percentage of Anish = ( 536 × 100) ÷ ( 600)

➝ Percentage of Anish = 53600 ÷ 600

➝ Percentage of Anish = 89.33%

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Form above it is clear that,

• Percentage obtained by Aman = 82%
• Percentage obtained by Anish = 89.33%

It is clear that , Anish has obtained more Percentage than Aman and hence performance of Anish is better than Aman

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ANSWER :

• Percentage obtained by Aman = 82%
• Percentage obtained by Anish = 89.33%
• Performance of Anish is better than Aman