Math, asked by SaiPradyumnan3904, 1 year ago

Aman's age is ten times his son's age. Ten years ago he was 5 times his son's age find their present ages

Answers

Answered by Gokulaesh
1

let son age be x

let aman age be 10x

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Ten years ago....

son age  x-10

aman age  10x-10

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5(x-10) = 10x-10

5x - 50 = 10x- 10

5x = 40

x= 8

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son age = 8

aman age = 8 x 10

                 =  80

Answered by Anonymous
4

To Find:

The present ages of Aman and his son.

Solution:

Let the age of Aman's son be x and Aman will be 2x

According to the question,

5(x-10)=3x-10\\\implies 5x-50=3x-10\\\implies 5x-3x=-10+50\\\implies 2x = 40

Now, finding the value of x

\implies x=\frac{40}{2} \\\implies x = 20

Therefore,

Aman's son's age = x=\boxed{20}

Aman's age = 3x =3 \times 20 = \boxed{60 \: years}

Hence, Aman's son's age is 20 years and Aman's age is 60 years.

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