Math, asked by jay3520, 10 months ago

Aman's age is three times his son's age .Ten years ago he was five times his son's age. find their present ages​

Answers

Answered by Darvince
17

Answer:

Aman is 45 years old and his son is 15 years old.

Step-by-step explanation:

Given :

Aman's age = three times his son's age

Tens years ago = he was five times his son's age

To find :

Their present Ages

Solution :

Let the Present Ages be -

  • Son as x
  • Aman as 3x

Ages 10 Years back =

  • Son as (x - 10)
  • Aman as (3x - 10)

According to the Question -

Ten years ago he was five times his son's age

➠ (3x - 10) = 5(x - 10)

➠ 3x - 10 = 5x - 50

➠ 3x - 5x = - 50 + 10

➠ - 2x = - 30

➠ x = 30/2

➠ x = 15

Son is Presently = 15 years old

Aman's age =

➠ 3x

➠ 3(15)

➠ 45

Aman = 45 years

\therefore Aman is 45 years old and his son is 15 years old.

Answered by MarshmellowGirl
20

{\textbf{Answer}}

____________________________________________________________

Let Aman’s son’s age be x years.

Therefore, Aman’s age will be 3x years.

Ten years ago, their age was (x − 10) years and (3x − 10) years respectively.

According to the question,

10 years ago, Aman’s age = 5 × Aman’s son’s age 10 years ago.

3x − 10 = 5(x − 10)

3x − 10 = 5x − 50

Transposing 3x to R.H.S and 50 to L.H.S, we obtain

50 − 10 = 5x − 3x

40 = 2x

Dividing both sides by 2, we obtain

20 = x

Aman’s son’s age = x years = 20 years

Aman’s age = 3x years = (3 × 20) years = 60 years

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